I have application with 3 forms , Parent and 2 child forms with names fristForm and secondForm.
On parent form at public Form() I open the firstForm. as follow :
firstForm _firstForm = new firstForm(); // Code on Parent
public Form1() {
InitializeComponent();
firstForm _firstForm .MdiParent = this;
_firstForm .Show();
}from firstForm I call function from Parent Form as follow : _
public void _closeDb(firstForm _formReceive)
{
_firstForm = _formReceive;
_firstForm .Close();
// Open the SecondForm
scondForm _secondForm = new secondForm();
_secondForm.MdiParent = this;
_secondForm.shwo();
}But the scondForm not Open , Can any one help be to open the form
Best Regards
Swalf